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4.9x^2-43.8x-7=0
a = 4.9; b = -43.8; c = -7;
Δ = b2-4ac
Δ = -43.82-4·4.9·(-7)
Δ = 2055.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43.8)-\sqrt{2055.64}}{2*4.9}=\frac{43.8-\sqrt{2055.64}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43.8)+\sqrt{2055.64}}{2*4.9}=\frac{43.8+\sqrt{2055.64}}{9.8} $
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